How to choose the right Solar Inverter for your appliance?

In recent years, SUNVIS has launched a variety of solar off-grid inverters, including pure sine wave inverters and high frequency pure sine wave inverters, the power level from 300W to 30KW, the input voltage level covers the 12V/24V/48V/110V/220V, which can meet various applications.

Based on the digital intelligent design, advanced SPWM Technologe, voltage and current double closed-loop control and fully isolated inverter technology ensure the product has high quality electrical parameters, strong load shock resistance; the product has high reliability, high efficiency, simple appearance, complete protection function, easy installation, easy operation and other features. Suitable for household appliances, power tools, industrial equipment, electronic audio-visual and other AC loads, as well as solar photovoltaic power generation systems, such as vehicle inverter application systems, solar caravans, solar household, solar yachts and solar power plants and other fields.

How to choose the appropriate inverter when the type of load and power are known?

First, the type of AC load, nominal power, power factor, and starting shock factor need to be determined. The maximum power of the load is then calculated according to the formula: load maximum power = (nominal power/power factor)*starting shock factor; load sustained power = nominal power/power factor, the sustained power of the load is calculated. Finally, it is sufficient to follow the principle that the continuous output power of the inverter should be greater than the continuous power equal to the load and that the overload power allowed by the inverter is greater than the maximum power of the load.

Example 1: 100W incandescent lamp, it is a resistive load, power factor 1, start shock factor is 1. Therefore, its maximum power is 100W, as long as the inverter power is greater than 100W can be.

Example 2: air conditioner (non-inverter), inductive load, power 735W, power factor 0.9, start shock factor is 5. then its maximum power = (735W/0.9)*5 = 4105VA; continuous working power = 735W/0.9 = 817VA. so the rated power of the inverter should be greater than 817W, the allowed overload power should be greater than 4105W to drive this air conditioner.

The above table is for reference only, customers need to choose the appropriate inverter model according to the actual load characteristics.